

A327342


a(n) gives the number of distinct odd prime divisors of m(n) = A002559(n) (Markoff numbers).


2



0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 1, 1, 2, 1, 2, 1, 2, 2, 2, 1, 1, 2, 1, 2, 2, 2, 1, 2, 3, 3, 2, 1, 2, 1, 1, 2, 2, 2, 2, 3, 1, 1, 3, 1, 1, 2, 3, 2, 2, 2, 3, 2, 1, 3, 3, 2, 3, 1, 3, 3, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 1, 3, 2, 1, 4, 1, 2, 2, 4, 2, 1, 3, 3, 4, 3, 1, 1, 2, 2, 2, 1, 3, 2, 3, 2
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OFFSET

1,12


COMMENTS

These sequence members appear as exponents of 2 in the number of representative parallel primitive forms for binary quadratic forms of discriminant Disc(n) = 9*m(n)^2  4 and representation of m(n)^2. The reduced (primitive) principal form of this discriminant is F_p(n; X, Y) = X^2 + b(n)*X*Y  b(n)*Y^2, written also as F_p(n) = [1, b(n), b(n)], with b(n) = 3*m(n)  2 = A324250(n). This form representing m(n)^2 is important for the determination of Markoff triples MT(n).
For more details see A327343(n) = 2^a(n). The FrobeniusMarkoff uniqueness conjecture on ordered triples with largest member m(n) is certainly true for m(n) if a(n) = 0 (socalled singular cases) or 1. See the Aigner reference, p. 59, Corollary 3.20, for n >= 3 (the a(n) = 1 cases).


REFERENCES

Martin Aigner, Markov's Theorem and 100 Years of the Uniqueness Conjecture, Springer, 2013.


LINKS

Table of n, a(n) for n=1..100.


FORMULA

a(n) = number of distinct odd prime divisors of m(n) = A002559(n), for n >= 1.


EXAMPLE

For the examples a(6) = 1 and a(12) = 2 see A327343.


CROSSREFS

Cf. A002559, A324250, A327343.
Sequence in context: A058745 A275333 A108393 * A297828 A062245 A062246
Adjacent sequences: A327339 A327340 A327341 * A327343 A327344 A327345


KEYWORD

nonn,easy


AUTHOR

Wolfdieter Lang, Sep 11 2019


STATUS

approved



