OFFSET
1,3
LINKS
Colin Barker, Table of n, a(n) for n = 1..1000
Richard J. Mathar, Lozenge tilings of the equilateral triangle, arXiv:1909.06336 [math.CO], 2019.
Index entries for linear recurrences with constant coefficients, signature (5,-10,10,-5,1).
FORMULA
a(n) = (3/8)*(n-2)*(n-1)*(3*n^2 + 3*n - 4) (conjectured by R. J. Mathar, proved by Greg Dresden and E. Sijaric).
From Colin Barker, Jul 01 2019: (Start)
G.f.: 3*x^3*(4 - x)*(2 + x) / (1 - x)^5.
a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5) for n>5.
(End)
E.g.f.: (3/8)*exp(x)*x^2*(32 + 24*x + 3*x^2). - Stefano Spezia, Jul 01 2019
EXAMPLE
We can represent a unit triangle this way:
o
/ \
o - o
and a unit "lozenge" or "diamond" has these three orientations:
o
/ \ o - o o - o
o o and / / and also \ \
\ / o - o o - o
o
and for n=3, here is one of the 24 different tiling of the triangle of side length 3 with exactly two lozenges:
o
/ \
o o
/ \ / \
o - o - o
/ / \ / \
o - o - o - o
MATHEMATICA
Rest@ CoefficientList[Series[3 x^3*(4 - x) (2 + x)/(1 - x)^5, {x, 0, 37}], x] (* Michael De Vlieger, Jul 04 2019 *)
PROG
(PARI) concat([0, 0], Vec(3*x^3*(4 - x)*(2 + x) / (1 - x)^5 + O(x^40))) \\ Colin Barker, Jul 01 2019
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Greg Dresden, Jul 01 2019
STATUS
approved