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%I #10 Oct 18 2019 16:51:40
%S 2,6,8,16,18,22,24,40,42,46,48,56,58,62,64,96,98,102,104,112,114,118,
%T 120,136,138,142,144,152,154,158,160,224,226,230,232,240,242,246,248,
%U 264,266,270,272,280,282,286,288,320,322,326,328,336,338,342,344,360,362,366,368
%N Steinhaus sums.
%H Sandor Csörgö, Gordon Simons, <a href="http://www.math.uni.wroc.pl/~pms/files/14.2/Abstract/14.2.1.abs.pdf">On Steinhaus' resolution of the St. Petersburg paradox</a>, Probab. Math. Statist. 14 (1993), 157--172. MR1321758 (96b:60017). See p. 163 and Table 1 p. 171.
%F a(n) = Sum_{k>=1} floor(n/2^k + 1/2)*2^k.
%F a(n) = 2 * A006520(n-1).
%o (PARI) a(n) = sum(k=1, 1+log(n)\log(2), floor(n/2^k+1/2)*2^k);
%Y Cf. A000523 (log_2(n)), A006520.
%K nonn
%O 1,1
%A _Michel Marcus_, Oct 17 2019
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