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A325725 a(n) is defined by the condition that the decimal expansion of the Sum_{n>=1} 1/(Sum_{k=1..n} a(k)) = 1/a(1) + 1/(a(2)-a(1)) + 1/(a(3)-a(2)+a(1)) + ... begins with the concatenation of these numbers; also a(1) = 3 and a(n) > a(n-1). 2

%I #14 Jun 07 2019 08:57:21

%S 3,53,5254,942711270,60527555104759884,

%T 6079815437830353357655363418656533,

%U 36605822957679968262595918562001251109330115418597396926274122249725

%N a(n) is defined by the condition that the decimal expansion of the Sum_{n>=1} 1/(Sum_{k=1..n} a(k)) = 1/a(1) + 1/(a(2)-a(1)) + 1/(a(3)-a(2)+a(1)) + ... begins with the concatenation of these numbers; also a(1) = 3 and a(n) > a(n-1).

%C At any step only the least value greater than a(n) is taken into consideration. In fact, instead of 53, as a(2) we could choose 76, 367, 3366, 3666, 33367, 34350, 333366, ...

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/EgyptianFraction.html">Egyptian fraction</a>

%e 1/3 = 0.3333...

%e 1/3 + 1/(53-3) = 0.353333...

%e 1/3 + 1/(53-3) + 1/(5254-53+3) = 0.3535254932...

%e The sum is 0.3 53 5254 ...

%p P:=proc(q, h) local a, b, d, n, t, z; a:=1/h; b:=length(h);d:=h; print(d); t:=h;

%p for n from t+1 to q do z:=evalf(evalf(a+1/(n-t),100)*10^(b+length(n)), 100);

%p z:=trunc(z-frac(z)); if z=d*10^length(n)+n then b:=b+length(n);

%p d:=d*10^length(n)+n; t:=n-t; a:=a+1/t; print(n); fi; od; end: P(10^20, 3);

%Y Cf. A304288, A304289, A305661, A305662, A305663, A305664, A305665, A305666, A305667, A305668, A307007, A307020, A307021, A307022, A320023, A320284, A320306, A320307, A320308, A320309, A320335, A320336, A324222, A324223, A325726, A325727, A325728.

%K nonn,base

%O 1,1

%A _Paolo P. Lava_, May 17 2019

%E a(4) - a(7) from _Giovanni Resta_, May 17 2019

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Last modified April 18 22:18 EDT 2024. Contains 371782 sequences. (Running on oeis4.)