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A324683
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Starting at n, a(n) is the number of times we move from a negative position to a spot we have already visited according to the following rules. On the k-th step (k=1,2,3,...) move a distance of k in the direction of zero. If the number landed on has been landed on before, move a distance of k away.
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1
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0, 0, 0, 0, 0, 0, 0, 52, 0, 0, 0, 0, 6, 6, 0, 0, 0, 33300, 0, 0, 4302, 0, 0, 0, 0, 58682, 0, 0, 0, 6, 154594, 18830, 18829, 18829, 18829, 0, 0, 2, 10283, 10282, 3, 1, 0, 0, 29, 0, 5, 3, 3, 3, 3, 5, 2, 0, 0, 0, 9, 9, 9, 21706, 21705, 21705, 21705, 21705, 1, 0
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OFFSET
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0,8
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LINKS
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EXAMPLE
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For n=41, the points visited are 41, 40, 38, 35, 31, 26, 20, 13, 5, -4, 6, -5, 7, -6, 8, -7, 9, -8, 10, -9, 11, -10, 12, -11, -35, -60, -34, -61, -33, -62, -32, -1, -33, 0. The only time we revisit a spot is when we move from -1 to -33. As this only occurs for one negative number, a(41)=1.
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PROG
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(Python)
#Sequences A324660-A324692 generated by manipulating this trip function
#spots - positions in order with possible repetition
#flee - positions from which we move away from zero with possible repetition
#stuck - positions from which we move to a spot already visited with possible repetition
def trip(n):
stucklist = list()
spotsvisited = [n]
leavingspots = list()
turn = 0
forbidden = {n}
while n != 0:
turn += 1
sign = n // abs(n)
st = sign * turn
if n - st not in forbidden:
n = n - st
else:
leavingspots.append(n)
if n + st in forbidden:
stucklist.append(n)
n = n + st
spotsvisited.append(n)
forbidden.add(n)
return {'stuck':stucklist, 'spots':spotsvisited,
'turns':turn, 'flee':leavingspots}
#Actual sequence
def a(n):
d = trip(n)
return sum(1 for i in d['stuck'] if i < 0)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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