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A323375
Let f(p, q) denote the pair (p + q, wt(p) + wt(q)). a(n) gives the number of iterations of f starting at (n, 1) needed to make p/q an integer, or if no integer is ever reached then a(n) = -1. (Here wt is binary weight, A000120.)
3
1, 3, 3, 3, 1, 2, 1, 11, 4, 10, 1, 3, 4, 9, 2, 19, 1, 18, 1, 1, 7, 17, 7, 7, 6, 5, 6, 6, 1, 4, 15, 5, 16, 4, 1, 2, 4, 3, 1, 14, 3, 13, 13, 13, 12, 12, 1, 6, 12, 2, 5, 5, 11, 1, 5, 13, 10, 4, 1, 12, 3, 9, 3, 3, 1, 2, 1, 1, 40, 2, 8, 8, 39, 3, 7, 7, 9, 2, 3, 1, 3, 37, 37, 37, 5, 36, 36, 3, 1, 8
OFFSET
1,2
EXAMPLE
n=8; (8, 1) -> (9, 2) -> (11, 3) -> (14, 5) -> (19, 5) -> (24, 5) -> (29, 4) -> (33, 5) -> (38, 4) -> (42, 4) -> 46, 4) -> (50, 5). 50/5 = 10, so a(8) = 11 because it needs 11 iterations until p/q is an integer.
PROG
(PARI) f(v) = return([v[1]+v[2], hammingweight(v[1])+hammingweight(v[2])]);
a(n) = {my(nb = 0, v = [n, 1]); while (1, v = f(v); nb++; if (frac(v[1]/v[2]) == 0, return (nb))); } \\ Michel Marcus, Jan 13 2019
CROSSREFS
Sequence in context: A119560 A172364 A323596 * A140366 A167817 A153401
KEYWORD
nonn,base
AUTHOR
Ctibor O. Zizka, Jan 12 2019
STATUS
approved