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A323202
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Expansion of (1 - x) * (1 - x^3) / (1 - x^4) in powers of x.
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0
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1, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0, -1, 2, -1, 0
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OFFSET
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0,5
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LINKS
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FORMULA
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a(n) = -b(n) and b() is multiplicative with b(2) = 0, b(2^e) = -2 if e>1, b(p^e) = 1 if p>2.
Euler transform of length 4 sequence [-1, 0, -1, 1].
Moebius transform is length 4 sequence [-1, 1, 0, 2].
G.f.: (1 - x) * (1 - x^3) / (1 - x^4) = -1 + 1 / (1 + x) + 1 / (1 + x^2).
a(n) = a(-n) for all n in Z. a(n+2) = a(n-2) except if n=2 or n=-2.
a(n) = (-1)^n * A098178(n), a(2*n + 1) = -1, a(4*n + 2) = 0 for all n in Z.
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EXAMPLE
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G.f. = 1 - x - x^3 + 2*x^4 - x^5 - x^7 + 2*x^8 - x^9 - x^11 + ...
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MATHEMATICA
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a[ n_] := (-1)^n + If[Mod[n, 2] == 0, (-1)^(n/2), 0] - Boole[n == 0];
a[ n_] := {-1, 0, -1, 2}[[Mod[n, 4, 1]]] - Boole[n == 0];
a[ n_] := SeriesCoefficient[ (1 - x) (1 - x^3) / (1 - x^4), {x, 0, Abs@n}];
LinearRecurrence[{-1, -1, -1}, {1, -1, 0, -1}, 80] (* Harvey P. Dale, May 31 2021 *)
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PROG
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(PARI) {a(n) = (-1)^n + if(n%2==0, (-1)^(n/2)) - (n==0)};
(PARI) {a(n) = [2, -1, 0, -1][n%4 + 1] - (n==0)};
(PARI) {a(n) = n = abs(n); polcoeff( (1 - x) * (1 - x^3) / (1 - x^4) + x * O(x^n), n)};
(PARI) {a(n) = my(e); n=abs(n); if( n<1, n==0, e=valuation(n, 2); -if( e<2, 1-e, -2))};
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CROSSREFS
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KEYWORD
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sign,easy
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AUTHOR
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STATUS
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approved
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