OFFSET
1,2
COMMENTS
It is not known if sqrt(2) is normal, but the distribution of decimal digits found for the first 10^n digits of sqrt(2) shows no statistically significant departure from a uniform distribution.
LINKS
Eric Weisstein's World of Mathematics, Pythagoras's Constant Digits.
MAPLE
a:=proc(n)
local digits, SQRT2, C, i;
digits:=10^n+100;
SQRT2:=convert(frac(evalf[digits](sqrt(2))), string)[2..digits-99];
C:=0;
for i from 1 to length(SQRT2) do
if SQRT2[i]="8" then C:=C+1; fi;
od;
return(C);
end;
MATHEMATICA
Table[DigitCount[IntegerPart[(Sqrt[2]-1)*10^10^n], 10, 8], {n, 1, 10}] (* Robert Price, Mar 29 2019 *)
CROSSREFS
KEYWORD
nonn,base,more
AUTHOR
Martin Renner, Dec 21 2018
STATUS
approved