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%I #9 Dec 21 2018 18:57:03
%S 0,0,1,0,-1,0,3,0,-3,1,4,1,-2,0,3,0,-3,-1,2,-1,-4,0,1,0,-1,3,4,3,2,0,
%T 8,0,-8,-3,-2,-3,-4,1,5,1,-3,4,13,4,-5,1,2,1,0,-2,5,-2,-9,0,7,0,-7,3,
%U 7,3,-1,0,11,0,-11,-3,2,-3,-8,-1,4,-1,-6,2,10,2
%N z(1) = 0, and for any n > 0, z(4*n-2) = z(n) + k(n), z(4*n-1) = z(n) + i*k(n), z(4*n) = z(n) - k(n) and z(4*n+1) = z(n) - i*k(n) where k(n) is the least positive integer not leading to a duplicate term in sequence z (and i denotes the imaginary unit); a(n) is the imaginary part of z(n).
%H Rémy Sigrist, <a href="/A322575/b322575.txt">Table of n, a(n) for n = 1..10000</a>
%H Rémy Sigrist, <a href="/A322575/a322575.gp.txt">PARI program for A322575</a>
%o (PARI) See Links section.
%Y See A322574 for the real part of z and additional comments.
%K sign,look
%O 1,7
%A _Rémy Sigrist_, Dec 17 2018
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