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a(n) = Sum_{d divides n} (-1)^(d + n/d) * d^11.
4

%I #16 Nov 22 2022 22:01:05

%S 1,-2049,177148,-4192257,48828126,-362976252,1977326744,-8585738241,

%T 31381236757,-100048830174,285311670612,-742649943036,1792160394038,

%U -4051542498456,8649804864648,-17583591913473,34271896307634,-64300154115093

%N a(n) = Sum_{d divides n} (-1)^(d + n/d) * d^11.

%H Seiichi Manyama, <a href="/A321808/b321808.txt">Table of n, a(n) for n = 1..10000</a>

%H J. W. L. Glaisher, <a href="https://books.google.com/books?id=bLs9AQAAMAAJ&amp;pg=RA1-PA1">On the representations of a number as the sum of two, four, six, eight, ten, and twelve squares</a>, Quart. J. Math. 38 (1907), 1-62 (see p. 4 and p. 8).

%H <a href="/index/Ge#Glaisher">Index entries for sequences mentioned by Glaisher</a>.

%F G.f.: Sum_{k>=1} (-1)^(k+1)*k^11*x^k/(1 + x^k). - _Ilya Gutkovskiy_, Dec 22 2018

%F Multiplicative with a(2^e) = -3*(341*2^(11*e+1) + 1365)/2047, and a(p^e) = (p^(11*e+11) - 1)/(p^11 - 1) for p > 2. - _Amiram Eldar_, Nov 22 2022

%t a[n_] := DivisorSum[n, (-1)^(# + n/#)*#^11 &]; Array[a, 50] (* _Amiram Eldar_, Nov 22 2022 *)

%o (PARI) apply( A321808(n)=sumdiv(n, d, (-1)^(n\d-d)*d^11), [1..30]) \\ _M. F. Hasler_, Nov 26 2018

%Y Column k=11 of A322083.

%Y Cf. A321543 - A321565, A321807 - A321836 for similar sequences.

%K sign,mult

%O 1,2

%A _N. J. A. Sloane_, Nov 23 2018