OFFSET
1,1
COMMENTS
a(n) <= A177415(n).
Each a(n) is an odd prime.
If k = A001567(n) is a Carmichael number, then a(n) = lpf(k).
Conjecture: if k = A001567(n) is semiprime, then a(n) < lpf(k).
The smallest numbers k = A001567(n) such that a(n) = prime(m) for m > 1 are 341, 1105, 1729, 75361, 29341, 162401, 334153, ... See A135720 > 561.
The smallest such semiprimes are 341, 2701, ?, 721801, ... Cf. A285549.
EXAMPLE
The first Fermat pseudoprime to base 2 is 341, and 341 is not a Fermat pseudoprime to base 3, so a(1) = 3.
MATHEMATICA
a[p_] := Module[{m=3}, While[Mod[m^(p-1), p] == 1, m++]; m]; psp = Select[Range[3, 1000000, 2], CompositeQ[ # ] && PowerMod[2, (# - 1), # ] == 1 &]; Map[a, psp] (* Amiram Eldar, Nov 19 2018 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Thomas Ordowski, Nov 19 2018
EXTENSIONS
More terms from Amiram Eldar, Nov 19 2018
STATUS
approved