

A321667


(3/2) * n^(2/3) rounded to nearest integer.


2



2, 2, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 10, 11, 11, 11, 12, 12, 12, 13, 13, 14, 14, 14, 14, 15, 15, 15, 16, 16, 16, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 20, 20, 20, 20, 21, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 24, 25, 25, 25, 25, 26, 26, 26, 26, 27
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OFFSET

1,1


COMMENTS

This is an approximation to the solution of the "Concrete Math Club" casino problem given in A079631.


REFERENCES

R. L. Graham, D. E. Knuth and O. Patashnik, Concrete Mathematics. 2nd Edition. AddisonWesley, Reading, MA, 1994. Section 3.2, pp. 7476.


LINKS

Hugo Pfoertner, Table of n, a(n) for n = 1..10000


MATHEMATICA

a[n_]:=Round[(3/2)*n^(2/3)]; Array[a, 50] (* Stefano Spezia, Nov 16 2018 *)


PROG

(PARI) for(j=1, 75, print1(round(1.5*j^(2/3)), ", "))
(Python) for n in range(1, 50): print(round((3/2)*n**(2/3)), end=', ') # Stefano Spezia, Nov 16 2018


CROSSREFS

Cf. A079631.
Sequence in context: A194177 A023190 A047783 * A194212 A194208 A057358
Adjacent sequences: A321664 A321665 A321666 * A321668 A321669 A321670


KEYWORD

nonn,easy


AUTHOR

Hugo Pfoertner, Nov 16 2018


STATUS

approved



