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 A319927 Numbers k such that the sum of the squares of the odd non-unitary divisors of k divides the sum of the squares of the non-unitary divisors of k. 2
 9, 18, 25, 27, 45, 49, 50, 54, 63, 75, 81, 90, 98, 99, 117, 121, 125, 126, 135, 147, 150, 153, 162, 169, 171, 175, 189, 198, 207, 225, 234, 242, 243, 245, 250, 261, 270, 275, 279, 289, 294, 297, 306, 315, 325, 333, 338, 342, 343, 350, 351, 361, 363, 369, 375, 378, 387, 405 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Conjecture: For any nonnegative integer power p the sum of the p-th powers of the odd non-unitary divisors of a(n) divides the sum of the p-th powers of the non-unitary divisors of a(n). LINKS Amiram Eldar, Table of n, a(n) for n = 1..10000 Eric Weisstein's World of Mathematics, Unitary Divisor Wikipedia, Unitary divisor EXAMPLE The non-unitary divisors of 18 are 3 and 6, of which only 3 is odd. 3^2=9 divides 3^3 + 6^2 = 45 and therefore 18 is in the sequence. MATHEMATICA sigmaNU[n_, p_]:=Total[Select[Divisors[n], GCD[#, n/#]>1&]^p]; sigmaNUOdd[n_, p_]:=Total[Select[Divisors[n], OddQ[#]&&GCD[#, n/#]>1&]^p]; p=2; (*if you want to check the conjecture for the power of 99, replace 2 with 99*) Select[Range, IntegerQ[sigmaNU[#, p]/sigmaNUOdd[#, p]]&]//Quiet PROG (PARI) su2(n) = sumdiv(n, d, if(gcd(d, n/d)!=1, d^2)); suo2(n) = sumdiv(n, d, if ((d%2) && (gcd(d, n/d)!=1), d^2)); isok(n) = my(suo = suo2(n)); if (suo, (su2(n) % suo) == 0); \\ Michel Marcus, Oct 28 2018 CROSSREFS Cf. A048105 (number, i.e., sum of the 0th powers, of non-unitary divisors of n), A034444 (number of unitary divisors of n). Sequence in context: A038837 A325359 A307579 * A034046 A069562 A072502 Adjacent sequences:  A319924 A319925 A319926 * A319928 A319929 A319930 KEYWORD nonn AUTHOR Ivan N. Ianakiev, Oct 02 2018 STATUS approved

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Last modified December 15 20:00 EST 2019. Contains 330000 sequences. (Running on oeis4.)