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 A319195 Irregular triangle with the unique representation of positive integers in the tribonacci ABC-representation. 0
 1, 0, 0, 1, 0, 2, 0, 0, 0, 1, 0, 1, 1, 0, 0, 2, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 1, 1, 0, 2, 1, 0, 0, 0, 2, 0, 1, 2, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 2, 0, 1, 0, 0, 0, 1, 1, 0, 1, 1, 1, 0, 0, 2, 1, 0, 0, 0, 0, 2, 0, 1, 0, 2, 0, 0, 1, 2, 0, 2, 2, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,6 COMMENTS The row length L(n) of this irregular triangle is A316714(n), n >= 1. This representation is based on the complementary and disjoint sets A, B and C given by the sequences A278040, A278039 and A278041, respectively. In the present notation sequences A, B and C are denoted by 1, 0 and 2. The numbers are represented by iterations of these sequences always starting with B(0) = 0 (in analogy to the Wythoff B sequence in the Fibonacci case). Uniqueness requires that the representations end in A(B(0)) or C(B(0)). B^[k](0) (k-fold iterations) for k >= 2 are forbidden. One could represent the number 0 by B(0), but this is not done here, because it is found that the ABC-representations of positive numbers is equivalent to the tribonacci representation of positive numbers given in A278038 for n >= 1 (n = 0 is not represented by T(1) = A000073(1) = 0. This representation uses the tribonacci numbers {T(k)}_{k >= 3} = {1, 2, 4, 7, 13, ...} for uniqueness reason). For this table the operation of sequences A, B and C is denoted by 1, 0 and 2, respectively, and the brackets and the final argument (0) of B(0) are not recorded. E.g., A(B(C(B(0)))) is written as 1020. Another form of this table is given in A316713 where A, B and C are denoted 2, 1 and 3, respectively. An equivalent such representation is given by A317206 using different complementary sequences A, B and C, related to our B = A278039,  A = A278040, and C = A278041: A(n) = A003144(n) = A278039(n-1) + 1, B(n) = A003145(n) =  A278040(n-1) + 1, C(n) = A003146(n) = A278041(n-1) + 1 with n >= 1. The present representation is the analog to the Wythoff representation of positive numbers (A189921 or A317208) using the Wythoff A and B sequences A000201 and A001950, respectively. The number length of the ABC-representation of n >= 1 is L(n) = A316714(n). The number of 0's (B's), 1's (A's) and 2's (C's) of the representation of n is A316715, A316716, A316717. LINKS Wolfdieter Lang, The Tribonacci and ABC Representations of Numbers are Equivalent, arXiv preprint arXiv:1810.09787 [math.NT], 2018. EXAMPLE The complementary and disjoint sequences A, B, C begin, for n >= 0: n: 0  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15  16  17  18  19  20  21  22 ... A: 1  5  8 12 14 18 21 25 29 32 36 38 42 45 49 52  56  58  62  65  69  73  76 ... B: 0  2  4  6  7  9 11 13 15 17 19 20 22 24 26 28  30  31  33  35  37  39  41 ... C: 3 10 16 23 27 34 40 47 54 60 67 71 78 84 91 97 104 108 115 121 128 135 141 ... --------------------------------------------------------------------------------- The ABC-representation of the positive integers begins:                                               #(1)   #(2)    #(3)    L(n) n = 1:      10               A(B(0)) =  1      1      1       0       2 n = 2:     010            B(A(B(0))) =  2      2      1       0       3 n = 3:      20               C(B(0)) =  3      1      0       1       2 n = 4:    0010         B(B(A(B(0)))) =  4      3      1       0       4 n = 5:     110            A(A(B(0))) =  5      1      2       0       3 n = 6:     020            B(C(B(0))) =  6      2      0       1       3 n = 7:   00010      B(B(B(A(B(0))))) =  7      4      1       0       5 n = 8:    1010         A(B(A(B(0)))) =  8      2      2       0       4 n = 9:    0110         B(A(A(B(0)))) =  9      2      2       0       4 n = 10:    210            C(A(B(0))) = 10      1      1       1       3 n = 11:   0020         B(B(C(B(0)))) = 11      3      0       1       4 n = 12:    120            A(C(B(0))) = 12      1      1       1       3 n = 13: 000010   B(B(B(B(A(B(0)))))) = 13      5      1       0       6 n = 14:  10010      A(B(B(A(B(0))))) = 14      3      2       0       5 n = 15:  01010      B(A(B(A(B(0))))) = 15      3      2       0       5 n = 16:   2010         C(B(A(B(0)))) = 16      2      1       1       4 n = 17:  00110      B(B(A(A(B(0))))) = 17      3      2       0       5 n = 18:   1110         A(A(A(B(0)))) = 18      1      3       0       4 n = 19:   0210         B(C(A(B(0)))) = 19      2      1       1       4 n = 20:  00020      B(B(B(C(B(0))))) = 20      4      0       1       5 ... CROSSREFS Cf. A000073, A000201, A001950, A189921, A003144, A003145, A003146, A278038, A278040, A278039, A278041, A316713, A316714, A316715, A316716, A316717, A317208. Sequence in context: A248911 A116681 A131371 * A003475 A248639 A293959 Adjacent sequences:  A319192 A319193 A319194 * A319196 A319197 A319198 KEYWORD nonn,tabf,easy AUTHOR Wolfdieter Lang, Sep 13 2018 STATUS approved

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Last modified May 25 17:36 EDT 2020. Contains 334595 sequences. (Running on oeis4.)