A319150 a(n) = gcd(A275286(n), A001818(n+1)) / A025549(n+1)^2.

1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 1, 1, 1, 1, 1, 1, 1, 1, 1, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1

Offset

0,28

Comments

A(n) = a(n)*A025549(n+1)^2 = gcd(B(n), C(n)).

B(n) = A275286(n).

C(n) = A001818(n+1).

At first gcd(B(n), C(n)) = A025549(n+1)^2, but from n = 27 to n = 37, gcd(B(n), C(n)) = 11*A025549(n+1)^2, and then comes back to normal, then equals 19*A025549(n+1)^2, comes back to normal again, and so on ...

Let S(n) = Sum_{k=0..n} ((-1)^k)/(2*k+1)^2 (S(n) is NOT an integer sequence).

Notice that when n approaches +oo, D(n) converges to Catalan's constant (A006752).

A294970(n) is equal to the numerator of S(n) (when reduced).

Therefore B(n)/A(n) = A294970(n)

A294971(n) is equal to the denominator of S(n) (when reduced).

Therefore C(n)/A(n) = A294971(n).

This sequence was used to study the expression B(n)/C(n) (which equals S(n)) in an attempt to find out if Catalan's constant is irrational.

Links

Table of n, a(n) for n=0..94.

Formula

Explicit formula:

a(n) = gcd( ((2*n+1)!!)^2 * (Sum_{i=0..n}((-1)^i)/(2*i+1)^2), ((2*n+1)!!)^2 ) / ( (((2*n+1)!!)^2) / ( lcm{1,3,5,...,2*n+1} ) )^2.

A few relations:

gcd(A275286(n), A001818(n+1)) = a(n)*A025549(n+1)^2 = A(n);

A275286(n)/A(n) = A294970(n);

A001818(n+1)/A(n) = A294971(n);

Lim_{n->+oo) A294970(n)/A294971(n) = G (Catalan's Constant, decimal expansion: A006257).

Example

For n = 5:
B(n) = A275286(5) = 98607816;
C(n) = A001818(5+1) = 108056025;
gcd(98607816,108056025) = A(5) = 9;
A025549(5+1)^2 = 3^2 = 9;
So a(5) = A(5)/A025549(5+1)^2 = 9/9 = 1.

Mathematica

a[n_] := GCD[(2n+1)!!^2 * Sum[(-1)^k/(2k+1)^2, {k, 0, n}], (2n+1)!!^2]*
LCM @@ Range[1, 2n+1, 2]^2 / ((2n+1)!!)^2; Array[a, 100, 0] (* Amiram Eldar, Nov 16 2018 *)

Prog

(PARI) dfo(n) = (2*n)! / n! / 2^n;
a6(n) = dfo(n+1)^2*sum(k=0, n, (-1)^k/(2*k+1)^2);
a8(n) = ((2*n)!/(n!*2^n))^2;
a9(n) = (((2*n)!/n!)/2^n)/lcm(vector(n, i, 2*i-1));
a(n) = gcd(a6(n) , a8(n+1)) / a9(n+1)^2; \\ Michel Marcus, Nov 08 2018

Crossrefs

Cf. A275286, A001818, A025549, A294970, A294971, A006257.

Sequence in context: A045538 A084066 A231472 * A112122 A290856 A010850

Adjacent sequences: A319147 A319148 A319149 * A319151 A319152 A319153

Keyword

nonn

Author

Tristan Cam, Nov 08 2018

Status

approved