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A316189
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Decimal expansion of Sum(1/p + 1/q) as (p, q) runs through the twin m^2 + 1 primes.
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0
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OFFSET
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0,1
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COMMENTS
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Or decimal expansion of (1/5 + 1/17) + Sum_{i>=0} (1/p(i) + 1/q(i)) where p(i) and q(i) are primes of the form p(i) = m^2 + 1 = (10*i+4)^2 + 1 and q(i) = (m + 2)^2 + 1 = (10*i + 6)^2 + 1 (for m > 1, m == 4 (mod 10)). See A096012.
The sum is convergent; it must be less than 0.81459657... (see A172168).
Conjecture: the series of all twin m^2 + 1 prime reciprocals converges to 0.357745147...
It is probable that a(9) = 1.
A good approximation to the constant is (2*log(7/3)/log(17))^2 = 0.35774506... which agrees with the constant through the first 6 significant digits.
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REFERENCES
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S. R. Finch, Mathematical Constants, Encyclopedia of Mathematics and its Applications, vol. 94, Cambridge University Press, pp. 94-98.
J. W. L. Glaisher, On the Sums of Inverse Powers of the Prime Numbers, Quart. J. Math. 25, 347-362, 1891.
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LINKS
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FORMULA
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Equals (1/5 + 1/17) + Sum_{n>=1} (1/(A096012(n)^2 + 1) + 1/(A096012(n) + 2)^2 + 1).
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EXAMPLE
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0.3577451... = (1/5 + 1/17) + (1/17 + 1/37) + (1/197 + 1/257) + ...
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MATHEMATICA
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s=N[1/5+1/17, 20]; Do[p=(10*k+4)^2+1; q=(10*k+6)^2+1; If[PrimeQ[p]&&PrimeQ[q], s=s+1/p+1/q], {k, 0, 10^7}]; Print[N[s, 20]]
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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