%I #31 Aug 24 2019 12:20:39
%S 2,5,258,262150,4294967320,1125899906842744,4722366482869645214416,
%T 316912650057057350374175806384,
%U 340282366920938463463374607431768251776,5846006549323611672814739330865132078623730534784,1606938044258990275541962092341162602522202993782792838930176
%N a(n) = 4^n^2 + n!.
%H Andrew M. Kamal, <a href="https://mentors4edu.github.io/New-Field/">New Field</a>
%e a(1) = 5 since 1^1=1, (4^1) + 1! = 5;
%e a(2) = 4^2^2 = 4^4 = 256, 256 + 2! = 256 + 2*1 = 258.
%Y Cf. A309669, A192366.
%K nonn
%O 0,1
%A _Andrew M. Kamal_, Aug 11 2019