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A309614 Digits of the 10-adic integer (31/9)^(1/3). 3
9, 1, 9, 8, 8, 1, 3, 3, 5, 8, 3, 9, 6, 0, 0, 9, 0, 6, 1, 9, 2, 8, 3, 4, 4, 7, 9, 1, 1, 5, 3, 2, 0, 1, 6, 9, 3, 2, 9, 2, 5, 9, 4, 0, 0, 4, 7, 9, 3, 2, 1, 0, 2, 1, 2, 7, 8, 7, 9, 2, 5, 1, 1, 5, 6, 3, 9, 3, 1, 7, 8, 5, 7, 1, 3, 2, 9, 4, 2, 5, 0, 2, 2, 4, 1, 5, 4, 0, 4, 2, 1, 5, 2, 0, 5, 5, 6, 2, 0, 8 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,1
LINKS
FORMULA
Define the sequence {b(n)} by the recurrence b(0) = 0 and b(1) = 9, b(n) = b(n-1) + 7 * (9 * b(n-1)^3 - 31) mod 10^n for n > 1, then a(n) = (b(n+1) - b(n))/10^n.
EXAMPLE
9^3 == 9 (mod 10).
19^3 == 59 (mod 10^2).
919^3 == 559 (mod 10^3).
8919^3 == 5559 (mod 10^4).
88919^3 == 55559 (mod 10^5).
188919^3 == 555559 (mod 10^6).
PROG
(PARI) N=100; Vecrev(digits(lift(chinese(Mod((31/9+O(2^N))^(1/3), 2^N), Mod((31/9+O(5^N))^(1/3), 5^N)))), N)
(Ruby)
def A309614(n)
ary = [9]
a = 9
n.times{|i|
b = (a + 7 * (9 * a ** 3 - 31)) % (10 ** (i + 2))
ary << (b - a) / (10 ** (i + 1))
a = b
}
ary
end
p A309614(100)
CROSSREFS
Sequence in context: A154697 A187368 A193670 * A154220 A133919 A145078
KEYWORD
nonn,base
AUTHOR
Seiichi Manyama, Aug 10 2019
STATUS
approved

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Last modified March 29 10:59 EDT 2024. Contains 371277 sequences. (Running on oeis4.)