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A309555
Triangle read by rows: T(n,k) = 3 + k*(n-k) for n >= 0, 0 <= k <= n.
5
3, 3, 3, 3, 4, 3, 3, 5, 5, 3, 3, 6, 7, 6, 3, 3, 7, 9, 9, 7, 3, 3, 8, 11, 12, 11, 8, 3, 3, 9, 13, 15, 15, 13, 9, 3, 3, 10, 15, 18, 19, 18, 15, 10, 3, 3, 11, 17, 21, 23, 23, 21, 17, 11, 3, 3, 12, 19, 24, 27, 28, 27, 24, 19, 12, 3, 3, 13, 21, 27, 31, 33, 33, 31, 27, 21, 13, 3, 3, 14, 23, 30, 35, 38, 39, 38, 35, 30, 23, 14, 3
OFFSET
0,1
COMMENTS
The rascal triangle (A077028) can be generated by either of the rules South = (East*West+1)/North or South = East+West+1-North; this number triangle can be generated by either of the rules South = (East*West+3)/North or South = East+West+1-North.
It is more suggestive to observe that N*S-E*W = 1 or 3 in the two cases, and (N+S)-(E+W) = 1 in both cases. In fact "3" in the present definition can be replaced by any integer c, and we get a triangle of integers with N*S-E*W = c and (N+S)-(E+W) = 1. I say "suggestive", because these rules also arise in frieze patterns. - N. J. A. Sloane, Aug 28 2019
LINKS
Philip K Hotchkiss, Generalized Rascal Triangles, arXiv:1907.11159 [math.HO], 2019.
FORMULA
By rows: a(n,k) = 3 + k(n-k), n >= 0, 0 <= k <= n.
By antidiagonals: T(r,k) = 3 + r*k, r,k >= 0.
EXAMPLE
For the row n=3: a(3,0)=3, a(3,1)=5, a(3,2)=5, a(3,3)=3, ...
For the antidiagonal r=2: T(2,0)=3, T(2,1)=5, T(2,3)=7, T(2,4)=9, ...
The triangle begins:
..............3..
............3..3..
..........3..4..3..
........3..5...5..3..
......3..6...7...6..3..
....3..7...9...9..7..3..
..3..8..11..12..11..8..3..
3..9..13..15..15..13..9..3.
...
MAPLE
T:= proc(n, k)
if n<0 or k<0 or k>n then
0;
else
k*(n-k)+3 ;
end if;
end:
seq(seq(T(n, k), k=0..n), n=0..12);
MATHEMATICA
T[n, k]:=k(n-k)+3; T[0, 0] = 3; Table[T[n, k], {n, 0, 12}, {k, 0, n}]//Flatten
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Philip K Hotchkiss, Aug 07 2019
EXTENSIONS
Missing a(50)=23 inserted by Georg Fischer, Nov 08 2021
STATUS
approved