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A309290
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Numbers k such that binomial(k^2,k) - k^2 is squarefree.
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2
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0, 2, 5, 7, 11, 17, 19, 23, 29, 31, 33, 35, 41, 43, 47, 59, 61, 65, 67, 71, 73, 77, 79, 83
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OFFSET
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1,2
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COMMENTS
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Sequence probably continues ..., 89, 97, ... [There is no composite term between 77 and 161 except possibly 133, 143 and 145. - M. F. Hasler, Feb 15 2022]
The sequence appears to contain most primes (except 3, 13, 37, 53, ...) and some semiprimes (33, 65, 77, ...). What can be said about these "exceptional" values? What are the first terms with more prime factors? The sequence remains nearly the same if k^2 is replaced by k^k. (Then 0 and 11 are not in the sequence but 3, 13, 37 and 53 are.) - M. F. Hasler, Jul 31 2019
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LINKS
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MATHEMATICA
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Select[Range[0, 50], SquareFreeQ[Binomial[#^2, #] - #^2] &] (* Vincenzo Librandi, Jul 31 2019 *)
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PROG
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(PARI) is(n)=issquarefree(binomial(n^2, n)-n^2)
for(n=0, oo, is(n) && print1(n, ", "))
(Magma) [0] cat [n: n in [2..45] | IsSquarefree(Binomial(n^2, n) - n^2)]; // Vincenzo Librandi, Jul 31 2019
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CROSSREFS
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Cf. A308078 (binomial(n^2,n) - n^n is squarefree), A309289 (binomial(2n,n) - n^2 is prime).
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KEYWORD
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nonn,hard,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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