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%I #21 May 06 2023 09:03:10
%S 10,12,11,12,8,10,10,10,10,10,9,11,10,11,7,9,9,9,9,9,6,10,0,9,6,6,6,6,
%T 6,6,8,11,9,10,6,8,8,8,8,8,9,7,6,6,7,8,9,9,9,9,10,9,6,8,8,7,9,10,10,
%U 10,12,9,6,8,9,9,7,10,12,12,13,9,6,8,9,10,10,7,12,13,14,9,6,8,9,10,12,12,7,13,14,9,6,8,9,10,12,13,13,7,6
%N Number of steps until the 'summarize the previous term' sequence enters a cycle.
%C The corresponding lengths of the cycle are given by A036225.
%C Is this a duplicate of A103618? - _R. J. Mathar_, May 05 2023
%e a(0) = 10, as shown by the 'summarize the previous term' sequence starting with 0: 0 -> 10 -> 1011 -> 1031 -> 102113 -> 10311213 -> 10411223 -> 1031221314 -> 1041222314 -> 1031321324 -> 1031223314 -> 1031223314 (see also A037220).
%Y Cf. A036225, A037220.
%K nonn,base
%O 0,1
%A _A.H.M. Smeets_, Jun 24 2019