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A308235 Take apart the sides of each of the integer-sided scalene triangles with perimeter n (at their vertices) and rearrange them orthogonally in 3-space so that their endpoints coincide at a single point. a(n) is the total surface area of all rectangular prisms enclosed in this way. 1
0, 0, 0, 0, 0, 0, 0, 0, 52, 0, 76, 94, 212, 126, 426, 328, 724, 624, 1130, 1020, 1938, 1540, 2648, 2568, 3910, 3432, 5482, 4970, 7364, 6850, 9616, 9072, 12954, 11696, 16086, 15576, 20544, 19152, 25698, 24240, 31530, 30072, 38148, 36630, 46870, 44022, 55240 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,9
LINKS
Wikipedia, Integer Triangle
FORMULA
a(n) = 2 * Sum_{k=1..floor((n-1)/3)} Sum_{i=k+1..floor((n-k-1)/2)} sign(floor((i+k)/(n-i-k+1))) * (i*k + i*(n-i-k) + k*(n-i-k)).
Conjectures from Colin Barker, May 16 2019: (Start)
G.f.: 2*x^9*(26 + 52*x + 90*x^2 + 97*x^3 + 94*x^4 + 71*x^5 + 56*x^6 + 31*x^7 + 17*x^8 + 5*x^9 + x^10) / ((1 - x)^5*(1 + x)^4*(1 + x^2)^3*(1 + x + x^2)^3).
a(n) = -2*a(n-1) - 2*a(n-2) + a(n-3) + 7*a(n-4) + 10*a(n-5) + 7*a(n-6) - 5*a(n-7) - 17*a(n-8) - 19*a(n-9) - 9*a(n-10) + 9*a(n-11) + 19*a(n-12) + 17*a(n-13) + 5*a(n-14) - 7*a(n-15) - 10*a(n-16) - 7*a(n-17) - a(n-18) + 2*a(n-19) + 2*a(n-20) + a(n-21) for n>21.
(End)
EXAMPLE
There is one integer-sided scalene triangle with perimeter 9: (2,3,4). The surface area of the enclosed rectangular prism is 2*(2*3 + 2*4 + 3*4) = 52. So a(9) = 52.
MATHEMATICA
2*Sum[Sum[(i*k + i*(n - i - k) + k*(n - i - k))*Sign[Floor[(i + k)/(n - i - k + 1)]], {i, k + 1, Floor[(n - k - 1)/2]}], {k, Floor[(n - 1)/3]}], {n, 100}]
CROSSREFS
Cf. A308233.
Sequence in context: A324683 A214373 A230299 * A022079 A230107 A275412
KEYWORD
nonn
AUTHOR
Wesley Ivan Hurt, May 16 2019
STATUS
approved

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Last modified April 23 10:29 EDT 2024. Contains 371905 sequences. (Running on oeis4.)