|
|
A307764
|
|
Numbers m whose distinct prime factors are exactly the same as the distinct prime factors of each of the numbers obtained by deleting any single digit in the decimal expansion of m.
|
|
0
|
|
|
2500, 3600, 9600, 25000, 36000, 96000, 250000, 360000, 960000, 2500000, 3600000, 9600000, 25000000, 36000000, 96000000, 250000000, 360000000, 960000000, 2500000000, 3600000000, 9600000000, 25000000000, 36000000000, 96000000000, 250000000000, 360000000000
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Conjecture: a(3n-2) = 25*10^(n+1), a(3n-1) = 36*10^(n+1) and a(3n) = 96*10^(n+1).
|
|
LINKS
|
|
|
EXAMPLE
|
3600 is in the sequence because 3600, 360, 600 and 300 contain all the same prime factors 2, 3 and 5.
|
|
MAPLE
|
with(numtheory):nn:=10^10:
for n from 100 to nn do:
it:=0:x:=convert(n, base, 10):n0:=nops(x):d:=factorset(n):
W:=array(1..n0-1):
for i from 1 to n0 do :
k:=0:
for j from n0 by -1 to 1 do:
if j<>i
then
k:=k+1: W[k]:=x[j]:
else
fi:
od:
s:=sum(‘W[i]*10^(n0-i-1)’, ‘i’=1..n0-1):d1:=factorset(s):
if d=d1
then
it:=it+1:
else
fi:
od:
if it=n0
then
printf(`%d, `, n):
else
fi:
od:
|
|
MATHEMATICA
|
rad[0] = 0; rad[n_] := Times @@ (First@# & /@ FactorInteger[n]); Select[Range[ 10^6], {rad[#]} == Union[rad /@ (FromDigits/@Subsets[(d = IntegerDigits[#]), {Length[d] - 1}])] &] (* Amiram Eldar, Jul 26 2019 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,base
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|