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%I #5 Apr 25 2019 22:44:14
%S 1,1,1,1,1,2,2,2,1,5,3,5,2,27,4,78,14,152,551,1331,7377
%N Number of partitions of n^4 into at most n fourth powers.
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/BiquadraticNumber.html">Biquadratic Number</a>
%e 10^4 =
%e 4^4 + 4^4 + 6^4 + 8^4 + 8^4 =
%e 2^4 + 4^4 + 4^4 + 4^4 + 4^4 + 4^4 + 4^4 + 4^4 + 8^4 + 8^4,
%e so a(10) = 3.
%Y Cf. A000583, A105152, A259793, A299169, A299195, A307644, A307738.
%K nonn,more
%O 0,6
%A _Ilya Gutkovskiy_, Apr 25 2019
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