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A307698
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Number of evolutionary duplication-loss-histories with n leaves of the caterpillar species tree with 4 leaves.
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6
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4, 39, 495, 7235, 115303, 1948791, 34379505, 626684162, 11722058693, 223870302588, 4349161774626, 85701267415112, 1709101664822416, 34432888701965454, 699810795294490974, 14331183304458656628, 295434131968070459359, 6125911207605272841753, 127680054133385458855845
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refs;
listen;
history;
text;
internal format)
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OFFSET
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1,1
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COMMENTS
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An evolutionary history of size n is an ordered rooted (incomplete) binary tree with n leaves describing the evolution of a gene family of a species in phylogenomics. The caterpillar species tree S of size k is a binary tree with k leaves, where any left child is a leaf. Any node of the history is associated to a unique node of S, where specifically every leaf is associated to a leaf of S. A history is created by the following process (note that intermediate trees in this process may not be valid histories): Start with a root node associated to the root of S. For a given tree in the growth process, choose a leaf and perform a duplication, speciation, or (speciation-)loss event. A duplication event creates two children both associated to the same node as its parent. A speciation or (speciation-)loss event can only occur if the node is associated to an internal node in S. In that case, a speciation event creates two children associated to the children of the node in S. A (speciation-)loss event creates only a left or right child, associated to the left or right child in S, respectively.
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LINKS
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FORMULA
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G.f.: 1/2 - (1/2)*sqrt(-4 - t*v + 3*t + 3*v) where t = sqrt(1 - 4*z), u = sqrt(-5 + 6*t + 4*z) and v = sqrt(-t*u + 3*t + 3*u - 4).
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EXAMPLE
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The caterpillar species tree with 4 leaves is equal to
a
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b 4
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c 3
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1 2
For convenience the internal nodes are labeled by a,b,c, and the leaves by 1,2,3,4. The associated nodes in the histories will be denoted by the same labels.
The a(1)=4 histories with n=1 leaf are created by the following growth process:
a a a a
/ / / \
b b b 4
/ / \
c c 3
/ \
1 2
after three loss events each.
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PROG
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(PARI) my(z = 'z + O('z^25), t = sqrt(1-4*z), u = sqrt(-5+6*t+4*z), v = sqrt(-t*u+3*t+3*u-4)); Vec(1/2-(1/2)*sqrt(-4-t*v+3*t+3*v)) \\ Michel Marcus, May 07 2019
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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