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A306330
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Squarefree n with >= 3 factors that admit idempotent factorizations n = p*q.
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5
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30, 42, 66, 78, 102, 105, 114, 130, 138, 165, 170, 174, 182, 186, 195, 210, 222, 246, 255, 258, 266, 273, 282, 285, 290, 318, 330, 345, 354, 366, 370, 390, 399, 402, 410, 426, 434, 435, 438, 455, 462, 465, 474, 498, 510, 518, 530, 534, 546, 555, 570, 582, 602
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OFFSET
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1,1
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COMMENTS
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An idempotent factorization of n is a way of writing n = p*q such that b^(k(p-1)(q-1)+1) is congruent to b mod n for any integer k >= 0 and any b in Z_n. For example, p = 19, q = 15 is an idempotent factorization of n = 285. All factorizations of semiprimes are idempotent, so this sequence is restricted to n with >= 3 factors. Idempotent factorizations have the property that p and q generate correctly functioning RSA keys, even if one or both are composite.
We show in the reference below that a bipartite factorization of a squarefree integer n = pq is idempotent if and only if lambda(pq) divides (p-1)(q-1).
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LINKS
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EXAMPLE
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30 = 5 * 6, 42 = 7 * 6, 66 = 11 * 6, 78 = 13 * 6, 102 = 17 * 6, 105 = 7 * 15, 114 = 19 * 6, 130 = 13 * 10 are the idempotent factorizations for the first 8 terms in the sequence. 210 = 10 * 21 is the smallest n with a fully composite idempotent factorization, one in which both p and q are composite. The number n = p * 6 is idempotent for any prime p >= 5.
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PROG
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(PARI) isok3(p, q, n) = frac((p-1)*(q-1)/lcm(znstar(n)[2])) == 0;
isok(n) = {if (issquarefree(n) && omega(n) >= 3, my(d = divisors(n)); for (k=1, #d\2, if ((d[k] != 1) && isok3(d[k], n/d[k], n), return (1); ); ); ); } \\ Michel Marcus, Feb 22 2019
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CROSSREFS
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Subsequence of A120944 (composite squarefree numbers).
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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