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A305833
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Triangle read by rows: T(0,0)=1; T(n,k) = 4*T(n-1,k) + T(n-2,k-1) for k = 0..floor(n/2); T(n,k)=0 for n or k < 0.
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1
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1, 4, 16, 1, 64, 8, 256, 48, 1, 1024, 256, 12, 4096, 1280, 96, 1, 16384, 6144, 640, 16, 65536, 28672, 3840, 160, 1, 262144, 131072, 21504, 1280, 20, 1048576, 589824, 114688, 8960, 240, 1, 4194304, 2621440, 589824, 57344, 2240, 24, 16777216, 11534336, 2949120, 344064, 17920, 336, 1
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OFFSET
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0,2
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COMMENTS
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The numbers in rows of the triangle are along skew diagonals pointing top-left in center-justified triangle given in A013611 ((1+4*x)^n).
The coefficients in the expansion of 1/(1-4x-x^2) are given by the sequence generated by the row sums.
The row sums are A001076 (Denominators of continued fraction convergent to sqrt(5)).
If s(n) is the row sum at n, then the ratio s(n)/s(n-1) is approximately 4.236067977...; a metallic mean (see A098317), when n approaches infinity.
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REFERENCES
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Shara Lalo and Zagros Lalo, Polynomial Expansion Theorems and Number Triangles, Zana Publishing, 2018, ISBN: 978-1-9995914-0-3, pp. 70, 72, 90, 373.
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LINKS
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FORMULA
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G.f.: 1 / (1 - 4*t*x - t^2).
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EXAMPLE
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Triangle begins:
1;
4;
16, 1;
64, 8;
256, 48, 1;
1024, 256, 12;
4096, 1280, 96, 1;
16384, 6144, 640, 16;
65536, 28672, 3840, 160, 1;
262144, 131072, 21504, 1280, 20;
1048576, 589824, 114688, 8960, 240, 1;
4194304, 2621440, 589824, 57344, 2240, 24;
16777216, 11534336, 2949120, 344064, 17920, 336, 1;
67108864, 50331648, 14417920, 1966080, 129024, 3584, 28;
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MATHEMATICA
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t[0, 0] = 1; t[n_, k_] := If[n < 0 || k < 0, 0, 4 t[n - 1, k] + t[n - 2, k - 1]]; Table[t[n, k], {n, 0, 12}, {k, 0, Floor[n/2]}] // Flatten
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CROSSREFS
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KEYWORD
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tabf,nonn,easy
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AUTHOR
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STATUS
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approved
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