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A303788
a(n) = Sum_{i=0..m} d(i)*5^i, where Sum_{i=0..m} d(i)*6^i is the base-6 representation of n.
3
0, 1, 2, 3, 4, 5, 5, 6, 7, 8, 9, 10, 10, 11, 12, 13, 14, 15, 15, 16, 17, 18, 19, 20, 20, 21, 22, 23, 24, 25, 25, 26, 27, 28, 29, 30, 25, 26, 27, 28, 29, 30, 30, 31, 32, 33, 34, 35, 35, 36, 37, 38, 39, 40, 40, 41, 42, 43, 44, 45, 45, 46, 47, 48, 49, 50, 50, 51, 52, 53, 54, 55
OFFSET
0,3
LINKS
EXAMPLE
16 = 24_6, so a(16) = 2*5 + 4 = 14.
17 = 25_6, so a(17) = 2*5 + 5 = 15.
18 = 30_6, so a(18) = 3*5 + 0 = 15.
19 = 31_6, so a(19) = 3*5 + 1 = 16.
PROG
(Ruby)
def f(k, ary)
(0..ary.size - 1).inject(0){|s, i| s + ary[i] * k ** i}
end
def A(k, n)
(0..n).map{|i| f(k, i.to_s(k + 1).split('').map(&:to_i).reverse)}
end
p A(5, 100)
(PARI) a(n) = fromdigits(digits(n, 6), 5); \\ Michel Marcus, May 02 2018
CROSSREFS
Sum_{i=0..m} d(i)*b^i, where Sum_{i=0..m} d(i)*(b+1)^i is the base (b+1) representation of n: A065361 (b=2), A215090 (b=3), A303787 (b=4), this sequence (b=5), A303789 (b=6).
Cf. A037465.
Sequence in context: A053757 A256562 A228297 * A366871 A319288 A106744
KEYWORD
nonn,base
AUTHOR
Seiichi Manyama, Apr 30 2018
STATUS
approved