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%I #11 Apr 29 2018 13:00:28
%S 1,-2,-16,-204,-3264,-60384,-1239912,-27591408,-655324704,
%T -16443029408,-432731364992,-11882079044992,-339084517212576,
%U -10026995732141760,-306530743192692480,-9669854410016300160,-314315622535266332160
%N a(n) = [x^n] (15! / Sum_{k=0..n} (k+15)!*x^k)^(1/8).
%H Seiichi Manyama, <a href="/A303673/b303673.txt">Table of n, a(n) for n = 0..439</a>
%p [seq(coeff(series((factorial(15)/add(factorial(k+15)*x^k,k=0..n))^(1/8), x,30),x,n),n=0..25)]; # _Muniru A Asiru_, Apr 29 2018
%o (PARI) N=66; x='x+O('x^N); Vec((15!/sum(k=0, N, (k+15)!*x^k))^(1/8))
%Y Cf. A077607, A303671, A303672.
%K sign
%O 0,2
%A _Seiichi Manyama_, Apr 28 2018
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