|
EXAMPLE
|
G.f.: A(x) = 1 + x + 7*x^2 + 223*x^3 + 12876*x^4 + 1041470*x^5 + 106367932*x^6 + 12976266030*x^7 + 1828572078504*x^8 + 291167594109079*x^9 + ...
such that [x^n] A(x)^(3*n+2) / (x*A(x)^3)' = 0 for n>1.
ILLUSTRATION OF DEFINITION.
The table of coefficients in A(x)^(3*n+2) / (x*A(x)^3)' begins:
n=0: [1, -4, -33, -1902, -149243, -15230208, -1876337625, -267941179110, ...];
n=1: [1, -1, -21, -1385, -118455, -12695769, -1615045187, -235896844893, ...];
n=2: [1, 2, 0, -760, -83692, -9927612, -1334925264, -201948321520, ...];
n=3: [1, 5, 30, 0, -44414, -6904812, -1034743200, -165997446000, ...];
n=4: [1, 8, 69, 922, 0, -3604176, -713169380, -127940381076, ...];
n=5: [1, 11, 117, 2033, 50252, 0, -368770482, -87667218244, ...];
n=6: [1, 14, 174, 3360, 107125, 3936174, 0, -45061548696, ...];
n=7: [1, 17, 240, 4930, 171483, 8235801, 394811962, 0, ...]; ...
in which the main diagonal consists of all zeros after the initial terms, illustrating that [x^n] A(x)^(3*n+2) / (x*A(x)^3)' = 0 for n>1.
RELATED SERIES.
A(x)^3 = 1 + 3*x + 24*x^2 + 712*x^3 + 40134*x^4 + 3211848*x^5 + 326090932*x^6 + 39631822680*x^7 + 5570315156529*x^8 + ...
(x*A(x)^3)' = 1 + 6*x + 72*x^2 + 2848*x^3 + 200670*x^4 + 19271088*x^5 + 2282636524*x^6 + 317054581440*x^7 + 50132836408761*x^8 + ...
log(A(x)) = x + 13*x^2/2 + 649*x^3/3 + 50541*x^4/4 + 5136491*x^5/5 + 631363729*x^6/6 + 90027008835*x^7/7 + 14517298906509*x^8/8 + 2603034994183642*x^9/9 + ...
|