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%I #13 Apr 24 2021 04:18:11
%S 1,9,9,8,2,4,8,9,5,6,9,8,3,8,7,3,8,3,0,4,1,5,9,9,2,5,1,1,9,3,0,6,8,7,
%T 2,8,1,1,8,2,3,9,7,6,9,6,9,0,3,0,3,8,7,1,5,8,3,1,2,6,8,9,5,4,5,4,9,6,
%U 1,7,9,6,4,4,1,6,8,4,5,7,7,6,2,3,8,2,5
%N Decimal expansion of the probability that a bullet, shot randomly at a cube that is thrown into the air, will pass through the opposite side.
%C The solution to the problem proposed and solved by Enoch Beery Seitz in 1882: "A cube is thrown into the air and a random shot fired through it; find the chance that the shot passes through the opposite side."
%C The corresponding probability for the 2D case is 1/2 - log(2)/Pi = 0.279364...
%D Stanley Rabinowitz, Problems and Solutions from the Mathematical Visitor 1877-1896, MathPro Press, 1991, page 26.
%H Enoch Beery Seitz, <a href="https://babel.hathitrust.org/cgi/pt?id=umn.31951000241746i;view=1up;seq=27">Problem 201</a>, The Mathematical Visitor, Vol. 2, No. 1 (1882), p. 21.
%H Benjamin Franklin Finkel, <a href="https://archive.org/details/mathematicalsolu00fink">A Mathematical Solution Book</a>, Kidder, Mo., Kibley, Cokely & Co., 1888, page 349.
%H Benjamin Franklin Finkel, <a href="http://www.jstor.org/stable/2968643">Biography: E. B. Seitz</a>, The American Mathematical Monthly, Vol. 1, No. 1 (1894), pp. 3-6.
%H John E. Zimmerman, <a href="http://sections.maa.org/ohio/ohio_masters/seitz.html">Enoch Beery Seitz 1846-1883</a>.
%F Equals ((4*sqrt(2)*arctan(1/sqrt(2)) + log(4/3) - Pi)/Pi.
%e 0.1998248956983873830415992511930687281182397696903038715831268954549617964416...
%t RealDigits[(4*Sqrt[2]*ArcTan[1/Sqrt[2]]+Log[4/3]-Pi)/Pi, 10, 100][[1]]
%K nonn,cons
%O 0,2
%A _Amiram Eldar_, Mar 01 2018
%E Offset corrected by _Amiram Eldar_, Apr 24 2021
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