|
%I #8 Jan 18 2018 07:51:35
%S 1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,100,110,111,112,113,114,
%T 115,116,117,118,119,122,133,144,155,166,177,188,199,200,211,220,221,
%U 222,223,224,225,226,227,228,229,233,244,255,266,277,288,299,300
%N Numbers whose base-10 digits d(m), d(m-1),..., d(0) have m=0 or else d(i) = d(i+1) for some i in {0,1,...,m-1}.
%C These numbers comprise the complement of the set of numbers in the union of A297146 and A297147.
%C Differs from A044821 first for 1001, which is in this sequence but not in A044821. - _R. J. Mathar_, Jan 17 2018
%e Base-10 digits of 65536: 6,5,5,3,6, so that 65536 is in the sequence.
%p read("transforms") :
%p isA297148 := proc(n)
%p local dgs,ud;
%p dgs := convert(n,base,10) ;
%p if nops(dgs) < 2 then
%p return true;
%p end if;
%p if 0 in DIFF(dgs) then
%p true;
%p else
%p false;
%p end if;
%p end proc:
%p for n from 1 to 300 do
%p if isA297148(n) then
%p printf("%d,",n) ;
%p end if;
%p end do: # _R. J. Mathar_, Jan 18 2018
%t a[n_, b_] := Sign[Differences[IntegerDigits[n, b]]]; z = 300;
%t b = 10; t = Table[a[n, b], {n, 1, 10*z}];
%t u = Select[Range[z], ! MemberQ[t[[#]], 0] && First[t[[#]]] == 1 &] (* A297146 *)
%t v = Select[Range[z], ! MemberQ[t[[#]], 0] && First[t[[#]]] == -1 &] (* A297147 *)
%t Complement[Range[z], Union[u, v]] (* A297148 *)
%Y Cf. A297146, A297147.
%K nonn,easy,base
%O 1,2
%A _Clark Kimberling_, Jan 15 2018
|
