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%I #4 Dec 11 2017 15:36:35
%S 1,1,1,1,4,1,1,8,8,1,1,17,24,17,1,1,46,82,82,46,1,1,114,316,444,316,
%T 114,1,1,289,1182,2868,2868,1182,289,1,1,757,4560,17783,35561,17783,
%U 4560,757,1,1,1964,17508,110554,368770,368770,110554,17508,1964,1,1,5118,67310
%N T(n,k)=Number of nXk 0..1 arrays with each 1 horizontally, vertically or antidiagonally adjacent to 2 or 3 neighboring 1s.
%C Table starts
%C .1....1.....1.......1.........1...........1.............1...............1
%C .1....4.....8......17........46.........114...........289.............757
%C .1....8....24......82.......316........1182..........4560...........17508
%C .1...17....82.....444......2868.......17783........110554..........688248
%C .1...46...316....2868.....35561......368770.......3939121........42629909
%C .1..114..1182...17783....368770.....6200926.....107541673......1896487480
%C .1..289..4560..110554...3939121...107541673....3068113721.....90097748288
%C .1..757.17508..688248..42629909..1896487480...90097748288...4427644444522
%C .1.1964.67310.4288144.457078213.33169242951.2600708602697.211857339895816
%H R. H. Hardin, <a href="/A296405/b296405.txt">Table of n, a(n) for n = 1..263</a>
%F Empirical for column k:
%F k=1: a(n) = a(n-1)
%F k=2: [order 9]
%F k=3: [order 20]
%F k=4: [order 52]
%e Some solutions for n=5 k=4
%e ..1..1..0..0. .1..1..1..1. .0..0..0..0. .0..1..1..1. .0..1..0..0
%e ..1..1..1..1. .1..0..1..0. .1..1..0..0. .1..0..0..1. .1..1..0..0
%e ..0..0..1..0. .0..0..0..0. .1..1..0..0. .1..1..0..1. .1..0..1..0
%e ..0..1..0..1. .1..1..0..1. .0..1..1..1. .0..1..0..1. .1..1..1..0
%e ..0..1..1..1. .1..0..1..1. .0..0..1..1. .1..1..1..1. .0..0..0..0
%K nonn,tabl
%O 1,5
%A _R. H. Hardin_, Dec 11 2017
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