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A295388
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a(n) is the least k > n such that n divides k, and n+1 divides k+1, and n+2 divides k+2.
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1
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7, 14, 63, 64, 215, 174, 511, 368, 999, 670, 1727, 1104, 2743, 1694, 4095, 2464, 5831, 3438, 7999, 4640, 10647, 6094, 13823, 7824, 17575, 9854, 21951, 12208, 26999, 14910, 32767, 17984, 39303, 21454, 46655, 25344, 54871, 29678, 63999, 34480, 74087, 39774, 85183
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OFFSET
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1,1
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LINKS
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FORMULA
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a(2n-1) = 8*n^3 - 1.
a(2n) = 4*n^3 + 6*n^2 + 4*n.
G.f.: (7 + 14*x + 35*x^2 + 8*x^3 + 5*x^4 + 2*x^5 + x^6)/(x^2 - 1)^4.
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EXAMPLE
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999 is the smallest integer k > 9 such that 9 divides k, 10 divides k+1, and 11 divides k+2. Therefore a(9)=999.
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MATHEMATICA
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f[n_] := Block[{k = 2 n}, While[ Mod[{k, k +1, k +2}, {n, n +1, n +2}] != {0, 0, 0}, k += n]; k]; Array[f, 45] (* or *)
CoefficientList[ Series[(7 + 14x + 35x^2 + 8x^3 + 5 x^4 + 2x^5 + x^6)/(x^2 - 1)^4, {x, 0, 50}], x] (* or *)
LinearRecurrence[{0, 4, 0, -6, 0, 4, 0, -1}, {7, 14, 63, 64, 215, 174,
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PROG
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(PARI) a(n) = {my(k=n+1); while ((k % n) || ((k+1) % (n+1)) || ((k+2) % (n+2)), k++); k; } \\ Michel Marcus, Feb 12 2018
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CROSSREFS
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Cf. A005563 (with only: n divides k, and n+1 divides k+1).
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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