login
A295295
Sum of squarefree divisors of the powerful part of n: a(n) = A048250(A057521(n)).
7
1, 1, 1, 3, 1, 1, 1, 3, 4, 1, 1, 3, 1, 1, 1, 3, 1, 4, 1, 3, 1, 1, 1, 3, 6, 1, 4, 3, 1, 1, 1, 3, 1, 1, 1, 12, 1, 1, 1, 3, 1, 1, 1, 3, 4, 1, 1, 3, 8, 6, 1, 3, 1, 4, 1, 3, 1, 1, 1, 3, 1, 1, 4, 3, 1, 1, 1, 3, 1, 1, 1, 12, 1, 1, 6, 3, 1, 1, 1, 3, 4, 1, 1, 3, 1, 1, 1, 3, 1, 4, 1, 3, 1, 1, 1, 3, 1, 8, 4, 18, 1, 1, 1, 3, 1
OFFSET
1,4
COMMENTS
The sum of the squarefree divisors of n whose square divides n. - Amiram Eldar, Oct 13 2023
FORMULA
Multiplicative with a(p) = 1 and a(p^e) = (p+1) for e > 1.
a(n) = A048250(n) / A092261(n).
a(n) = Sum_{d^2|n} d * mu(d)^2. - Wesley Ivan Hurt, Feb 13 2022
From Amiram Eldar, Sep 18 2023: (Start)
Dirichlet g.f.: zeta(s) * zeta(2*s-1) / zeta(4*s-2).
Sum_{k=1..n} a(k) ~ (3*n/Pi^2) * (log(n) + 3*gamma - 1 - 4*zeta'(2)/zeta(2)), where gamma is Euler's constant (A001620). (End)
a(n) = A048250(n) - A344137(n). - Amiram Eldar, Oct 13 2023
MATHEMATICA
Array[DivisorSum[#/Denominator[#/Apply[Times, FactorInteger[#][[All, 1]]]^2], # &, SquareFreeQ] &, 105] (* Michael De Vlieger, Nov 26 2017, after Jean-François Alcover at A057521 *)
f[p_, e_] := If[e == 1, 1, p+1] ; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Sep 18 2023 *)
PROG
(Scheme, with memoization-macro definec)
(definec (A295295 n) (if (= 1 n) n (let ((p (A020639 n)) (e (A067029 n))) (* (if (= 1 e) 1 (+ 1 p)) (A295295 (A028234 n))))))
(PARI) a(n) = my(f=factor(n)); for (i=1, #f~, if (f[i, 2]==1, f[i, 1]=1)); sumdiv(factorback(f), d, d*issquarefree(d)); \\ Michel Marcus, Jan 29 2021
KEYWORD
nonn,easy,mult
AUTHOR
Antti Karttunen, Nov 25 2017
STATUS
approved