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A295283 a(n) = 1 + number of distinct earlier terms that have common one bits with n in binary representation. 2
1, 1, 2, 1, 2, 2, 3, 1, 3, 3, 4, 2, 4, 4, 5, 1, 4, 3, 5, 3, 5, 5, 6, 1, 4, 4, 6, 4, 6, 6, 7, 1, 5, 5, 7, 5, 7, 7, 8, 2, 6, 6, 8, 6, 8, 8, 9, 1, 6, 5, 8, 5, 8, 7, 9, 3, 7, 7, 9, 7, 9, 9, 10, 1, 6, 6, 9, 5, 8, 8, 10, 4, 8, 8, 10, 8, 10, 10, 11, 1, 7, 7, 10, 5, 9 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
This sequence is a variant of A295277: here we count earlier terms with common one bits, there without common one bits.
The scatterplot of this sequence shares features with that of A295277 (see scatterplot in Links section).
Empirically, this sequence and A295277 have tight connections:
- let c be the sequence defined for any n > 0 by c(n) = a(n) + A295277(n),
- we have for any n > 0, c(n) <= c(n+1) <= c(n) + 1,
- let u be the sequence defined for any n > 0 by u(n) = least k such that a(k) = n,
- let v be the sequence defined for any n >= 0 by v(n) = least k such that A295277(k) = n,
- we have for any n > 0, u(n) + 1 = v(n).
LINKS
Rémy Sigrist, Colored scatterplot of the first 2^20 terms (where the color is function of min(A000120(a(n)),A000120((Max_{k=1..n-1} a(k))+2-a(n))))
FORMULA
a(2^n) = 0 for any n >= 0.
EXAMPLE
The first terms, alongside the distinct earlier terms with common one bits with n, are:
n a(n) Distinct earlier terms with common one bits with n
-- ---- --------------------------------------------------
1 1 {}
2 1 {}
3 2 {1}
4 1 {}
5 2 {1}
6 2 {2}
7 3 {1, 2}
8 1 {}
9 3 {1, 3}
10 3 {2, 3}
11 4 {1, 2, 3}
12 2 {4}
13 4 {1, 3, 4}
14 4 {2, 3, 4}
15 5 {1, 2, 3, 4}
16 1 {}
17 4 {1, 3, 5}
18 3 {2, 3}
19 5 {1, 2, 3, 5}
20 3 {4, 5}
PROG
(PARI) mx = 0; for (n=1, 85, v = 1 + sum(i=1, mx, bitand(i, n)!=0); print1 (v ", "); mx = max(mx, v))
CROSSREFS
Sequence in context: A316848 A139124 A024160 * A103284 A071287 A355731
KEYWORD
nonn,base
AUTHOR
Rémy Sigrist, Nov 19 2017
STATUS
approved

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Last modified April 16 18:22 EDT 2024. Contains 371750 sequences. (Running on oeis4.)