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A294414
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Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2), where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4.
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18
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1, 3, 10, 22, 43, 78, 136, 231, 387, 641, 1053, 1721, 2803, 4555, 7391, 11981, 19409, 31429, 50879, 82352, 133278, 215679, 349008, 564740, 913803, 1478600, 2392462, 3871123, 6263648, 10134836, 16398551, 26533456, 42932078, 69465607, 112397760, 181863444
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OFFSET
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0,2
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COMMENTS
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The complementary sequences a() and b() are uniquely determined by the titular equation and initial values. The initial values of each sequence in the following guide are a(0) = 1, a(2) = 3, b(0) = 2, b(1) = 4:
A294413: a(n) = a(n-1) + a(n-2) - b(n-1) + 6
A294414: a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2)
A294415: a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) + 1
A294416: a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) + n
A294417: a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) - n
A294418: a(n) = a(n-1) + a(n-2) + b(n-1) + 2*b(n-2)
A294419: a(n) = a(n-1) + a(n-2) + 2*b(n-1) + 2*b(n-2)
A294420: a(n) = a(n-1) + a(n-2) + 2*b(n-1) + b(n-2)
A294421: a(n) = a(n-1) + a(n-2) + 2*b(n-1) - b(n-2)
A294422: a(n) = a(n-1) + a(n-2) + b(n-1) - b(n-2) + 1
A294423: a(n) = a(n-1) + a(n-2) + b(n-1) - b(n-2) + n
A294424: a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) - 1
A294425: a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) - 2
A294426: a(n) = a(n-1) + 2*a(n-2) + b(n-1) + b(n-2) - 3
Conjecture: a(n)/a(n-1) -> (1 + sqrt(5))/2, the golden ratio.
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LINKS
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EXAMPLE
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a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4, so that
a(2) = a(1) + a(0) + b(1) + b(0) = 6
Complement: (b(n)) = (2, 4, 5, 6, 7, 8, 9, 11, 12, 13, ...)
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MATHEMATICA
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mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
a[0] = 1; a[1] = 3; b[0] = 2; b[1] = 4;
a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1] + b[n - 2];
b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
Table[a[n], {n, 0, 40}] (* A294414 *)
Table[b[n], {n, 0, 10}]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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