login
a(0) = a(1) = 1 and a(n) = n! * [x^n] exp((1/(1-x)^(n-1) - 1)/(n-1)) for n > 1.
2

%I #8 Oct 22 2017 07:27:34

%S 1,1,3,22,273,4956,122215,3909228,156878337,7694191648,451507161771,

%T 31157580173160,2493155105671153,228656777880920832,

%U 23802477358410219183,2788676280294791340496,364998736798930722881025,53020798447231578364796928

%N a(0) = a(1) = 1 and a(n) = n! * [x^n] exp((1/(1-x)^(n-1) - 1)/(n-1)) for n > 1.

%H Seiichi Manyama, <a href="/A293989/b293989.txt">Table of n, a(n) for n = 0..281</a>

%Y Main diagonal of A291709.

%K nonn

%O 0,3

%A _Seiichi Manyama_, Oct 21 2017