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 A293425 Primes of the form 2^a * 3^b * 5^c - 1 for positive a, b, c. 2
 29, 59, 89, 149, 179, 239, 269, 359, 449, 479, 599, 719, 809, 1439, 1499, 1619, 2399, 2699, 2879, 2999, 4049, 4799, 5399, 7499, 8999, 9719, 10799, 11519, 12149, 12959, 13499, 15359, 18749, 20249, 21599, 23039, 25919, 33749, 35999, 40499, 51839, 56249, 59999, 65609, 67499, 69119, 71999 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS a(n) is congruent to 29 (mod 30). LINKS Robert Israel, Table of n, a(n) for n = 1..10000 EXAMPLE a(1) = 29 = 2^1 * 3^1 * 5^1 - 1. a(2) = 59 = 2^2 * 3^1 * 5^1 - 1. a(3) = 89 = 2^1 * 3^2 * 5^1 - 1. a(4) = 149 = 2^1 * 3^1 * 5^2 - 1. a(5) = 179 = 2^2 * 3^2 * 5^1 - 1. list of (a, b, c): (1, 1, 1), (2, 1, 1), (1, 2, 1), (1, 1, 2), (2, 2, 1), (4, 1, 1), (1, 3, 1), (3, 2, 1), (1, 2, 2), (5, 1, 1), (3, 1, 2), (4, 2, 1), (1, 4, 1), (5, 2, 1), (2, 1, 3), (2, 4, 1), ... MAPLE N:= 10^6: # to get all terms < N R:= {}: for c from 1 to floor(log[5]((N+1)/6)) do for b from 1 to floor(log[3]((N+1)/2/5^c)) do      R:= R union select(isprime, {seq(2^a*3^b*5^c-1,              a=1..ilog2((N+1)/(3^b*5^c)))}) od od: sort(convert(R, list)); # Robert Israel, Oct 15 2017 MATHEMATICA With[{n = 10^5}, Sort@ Select[Flatten@ Table[2^a*3^b*5^c - 1, {a, Log2@ n}, {b, Log[3, n/(2^a)]}, {c, Log[5, n/(2^a*3^b)]}], PrimeQ]] (* Michael De Vlieger, Oct 11 2017 *) PROG (GAP) K:=10^5+1;; # to get all terms <= K. A:=Filtered([1..K], IsPrime);; A293425:=List(Positions(List(A, i->Elements(Factors(i+1))), [2, 3, 5]), i->A[i]); (PARI) lista(nn) = {forprime(p=2, nn, f = factor(p+1); if ((vecmax(f[, 1]) <= 5) && (#f~==3), print1(p, ", ")); ); } \\ Michel Marcus, Oct 09 2017 CROSSREFS Cf. A000040, A005105, A030433, A132236, A293194. Sequence in context: A042662 A128469 A132236 * A158477 A161928 A140340 Adjacent sequences:  A293422 A293423 A293424 * A293426 A293427 A293428 KEYWORD nonn AUTHOR Muniru A Asiru, Oct 09 2017 STATUS approved

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Last modified April 11 14:10 EDT 2021. Contains 342886 sequences. (Running on oeis4.)