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A292779
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Interpret the values of the Moebius function mu(k) for k = n to 1 as a balanced ternary number.
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3
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1, -2, -11, -11, -92, 151, -578, -578, -578, 19105, -39944, -39944, -571385, 1022938, 5805907, 5805907, -37240814, -37240814, -424661303, -424661303, 3062123098, 13522476301, -17858583308, -17858583308, -17858583308, 829430026135, 829430026135, 829430026135
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OFFSET
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1,2
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COMMENTS
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Balanced ternary is much like regular ternary, but with the crucial difference of using the digit -1 instead of the digit 2. Then some powers of 3 are added, others are subtracted.
Since the least significant digit is always 1, a(n) is never a multiple of 3.
If mu(n) = 0, then a(n) is the same as a(n - 1).
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LINKS
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FORMULA
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a(n) = Sum_{k = 1 .. n} mu(k) 3^(k - 1).
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EXAMPLE
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mu(1) = 1, so a(1) = 1 * 3^0 = 1.
mu(2) = -1, so a(2) = -1 * 3^1 + 1 * 3^0 = -3 + 1 = -2.
mu(3) = -1, so a(3) = -1 * 3^2 + -1 * 3^1 + 1 * 3^0 = -9 - 3 + 1 = -11.
mu(4) = 0, so a(4) = 0 * 3^3 + -1 * 3^2 + -1 * 3^1 + 1 * 3^0 = -9 - 3 + 1 = -11.
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MAPLE
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a:= proc(n) option remember; `if`(n=0, 0,
a(n-1)+3^(n-1)*numtheory[mobius](n))
end:
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MATHEMATICA
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Table[3^Range[0, n - 1].MoebiusMu[Range[n]], {n, 50}]
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PROG
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(PARI) a(n) = sum(k=1, n, moebius(k)*3^(k-1)); \\ Michel Marcus, Oct 01 2017
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CROSSREFS
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KEYWORD
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easy,sign,base
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AUTHOR
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STATUS
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approved
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