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%I #10 Sep 30 2017 16:06:43
%S 0,0,0,0,0,0,0,1,0,0,0,0,0,0,2,3,0,0,0,1,0,0,0,0,0,0,0,0,4,4,6,6,0,0,
%T 0,0,0,0,2,3,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,8,8,8,9,12,12,12,12,0,0,
%U 0,1,0,0,0,0,0,0,0,0,4,4,6,6,0,0,0,0,0,0,2,3,0,0,0,1,0,0,0,0,0,0,0,0,0,0,2,2,0,0,0,0,0,0,2,2,16,16,16,16,16,16
%N a(n) = A292255(A163511(n)).
%C Because A292255(n) = a(A243071(n)), the sequence works as a "masking function" where the 1-bits in a(n) (always a subset of the 1-bits in binary expansion of n) indicate the numbers that are either of the form 12k+5 or of the form 12k+7 in binary tree A163511 (or its mirror image tree A005940) on that trajectory which leads from the root of the tree to the node containing A163511(n).
%C The AND - XOR formulas just restate the fact that J(3|n) = J(-1|n)*J(-3|n), as the Jacobi-symbol is multiplicative (also) with respect to its upper argument.
%H Antti Karttunen, <a href="/A292256/b292256.txt">Table of n, a(n) for n = 0..8191</a>
%H <a href="/index/Bi#binary">Index entries for sequences related to binary expansion of n</a>
%H <a href="/index/Pri#prime_indices">Index entries for sequences computed from indices in prime factorization</a>
%F a(n) = A292255(A163511(n)).
%F a(n) = A292264(n) AND (A292274(n) XOR A292946(n)), where AND is bitwise-and (A004198) and XOR is bitwise-XOR (A003987).
%F a(n) = A292264(n) AND (A292271(n) XOR A292942(n)). [See comments].
%F For all n >= 0, a(n) + A292944(n) + A292254(n) = n.
%o (Scheme) (define (A292256 n) (A292255 (A163511 n)))
%Y Cf. A005940, A163511, A292255.
%Y Cf. also A292247, A292248, A292254, A292264, A292271, A292274, A292592, A292593, A292942, A292944, A292946 (for similarly constructed sequences).
%K nonn
%O 0,15
%A _Antti Karttunen_, Sep 28 2017
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