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A290913 p-INVERT of the positive integers, where p(S) = 1 - 7*S^2. 3
0, 7, 28, 119, 532, 2352, 10388, 45913, 202916, 896777, 3963288, 17515680, 77410200, 342112855, 1511961052, 6682082183, 29531331004, 130513137552, 576800248892, 2549157374953, 11265950967908, 49789649104601, 220044376637232, 972481802150208, 4297864230688560 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
Suppose s = (c(0), c(1), c(2), ...) is a sequence and p(S) is a polynomial. Let S(x) = c(0)*x + c(1)*x^2 + c(2)*x^3 + ... and T(x) = (-p(0) + 1/p(S(x)))/x. The p-INVERT of s is the sequence t(s) of coefficients in the Maclaurin series for T(x). Taking p(S) = 1 - S gives the "INVERT" transform of s, so that p-INVERT is a generalization of the "INVERT" transform (e.g., A033453).
See A290890 for a guide to related sequences.
LINKS
FORMULA
G.f.: (7 x)/(1 - 4 x - x^2 - 4 x^3 + x^4).
a(n) = 4*a(n-1) + a(n-2) + 4*a(n-3) - a(n-4).
a(n) = 7*A290914(n) for n >= 0.
MATHEMATICA
z = 60; s = x/(1 - x)^2; p = 1 - 7 s^2;
Drop[CoefficientList[Series[s, {x, 0, z}], x], 1] (* A000027 *)
u = Drop[CoefficientList[Series[1/p, {x, 0, z}], x], 1] (* A290913 *)
u/7 (* A290914 *)
LinearRecurrence[{4, 1, 4, -1}, {0, 7, 28, 119}, 30] (* Harvey P. Dale, Dec 26 2018 *)
CROSSREFS
Sequence in context: A037702 A359018 A302523 * A303406 A054626 A220361
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Aug 18 2017
STATUS
approved

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Last modified March 28 16:58 EDT 2024. Contains 371254 sequences. (Running on oeis4.)