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A289760
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Prime powers P for which the number of modulo P residues among sums of four sixth powers is less than P.
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2
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7, 8, 9, 13, 16, 27, 32, 49, 64, 81, 128, 169, 243, 256, 343, 512, 729, 961, 1024, 2048, 2187, 2197, 2401, 4096, 6561, 8192, 16384, 16807, 19683, 28561, 29791, 32768, 59049, 65536, 117649, 131072, 177147, 262144, 371293, 524288, 531441, 823543, 923521, 1048576
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OFFSET
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1,1
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COMMENTS
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If any prime power P = p^k (where p is prime and k >= 1) is in the sequence, then so is p^j for all j > k.
The sequence appears to consist of all numbers > 4 that are powers of 2, 3, 7, or 13, and all powers of 31 except 31 itself.
It appears that this sequence differs from the similar sequence for sums of five sixth powers only in that that sequence does not contain any powers of 31.
Conjecture: the largest prime in the sequence is 13.
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LINKS
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EXAMPLE
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5 is not in the sequence because (i^6 + j^6 + k^6 + m^6) mod 5, where j, k, and m are integers, can take on all 5 values 0..4.
7 is in the sequence because (i^6 + j^6 + k^6 + m^6) mod 7 can take on only 5 values (0..4), not 7.
14 is not in the sequence because -- although (i^6 + j^6 + k^6 + m^6) mod 14 can take on only the 10 (not 14) values 0, 1, 2, 3, 4, 7, 8, 9, 10, and 11 -- 14 is not a prime power.
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CROSSREFS
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Subsequence of A289740 (similar sequence for sums of three sixth powers).
Cf. A289631 (similar sequence for sums of two sixth powers).
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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