login
A289675
Consider the Post tag system described in A284116 (but adapted to the alphabet {1,2}) ; sequence lists the words that terminate in the empty word.
10
1, 2, 11, 12, 111, 112, 121, 122, 1111, 1121, 1211, 1221, 2111, 2121, 2211, 2221, 11111, 11112, 11121, 11122, 11211, 11212, 11221, 11222, 12111, 12112, 12121, 12122, 12211, 12212, 12221, 12222, 111111, 111112, 111121, 111122, 112111, 112112, 112121, 112122, 121111, 121112, 121121, 121122, 122111, 122112, 122121, 122122
OFFSET
1,2
COMMENTS
Post's tag system maps a word w over {1,2} to w', where if w begins with 1, w' is obtained by appending 11 to w and deleting the first three letters, or if w begins with 2, w' is obtained by appending 2212 to w and deleting the first three letters.
Under this Post tag system, some words when iterated end at the empty word, others go into cycles, and others may have an orbit which grows without limit. See A289670 and A289671 for the counts of the first two types. This sequence gives a list of the words that end at the empty word.
We work over {1,2} rather than the official alphabet {0,1} because of the prohibition in the OEIS of terms (other than 0 itself) which begin with 0.
Stillwell (2016, page 100) remarks that Post was unable to find an algorithm to determine which words belong to this sequence, "and in fact this particular `halting problem' remains unsolved to this day".
REFERENCES
John Stillwell, Elements of Mathematics: From Euclid to Goedel, Princeton, 2016. See page 100, Post's tag system.
LINKS
Emil L. Post, Formal Reductions of the General Combinatorial Decision Problem, Amer. J. Math. 65, 197-215, 1943. See page 204.
EXAMPLE
Working over the more usual alphabet {0,1}, the following are the orbits of the first few words that terminate at the empty word:
[0, -1]
[1, 01, 0, -1]
[00, 0, -1]
[01, 0, -1]
[000, 00, 0, -1]
[001, 00, 0, -1]
[010, 00, 0, -1]
[011, 00, 0, -1]
[0000, 000, 00, 0, -1]
[0010, 000, 00, 0, -1]
[0100, 000, 00, 0, -1]
[0110, 000, 00, 0, -1]
[1000, 01101, 0100, 000, 00, 0, -1]
[1010, 01101, 0100, 000, 00, 0, -1]
[1100, 01101, 0100, 000, 00, 0, -1]
[1110, 01101, 0100, 000, 00, 0, -1]
[00000, 0000, 000, 00, 0, -1]
...
Writing the initial words in this list over {1,2} rather than {0,1} gives the sequence.
MATHEMATICA
A289675 = {};
Do[For[i = 0, i < 2^n, i++, lst = {};
w = IntegerString[i, 2, n];
While[! MemberQ[lst, w],
AppendTo[lst, w];
If[w == "", AppendTo[A289675, IntegerString[i, 2, n]]; Break[]];
If[StringTake[w, 1] == "0", w = StringDrop[w <> "00", 3],
w = StringDrop[w <> "1101", 3]]]], {n, 6}];
Map[StringReplace[#, {"1" -> "2", "0" -> "1"}] &, A289675]
(* Robert Price, Sep 26 2019 *)
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Jul 30 2017
STATUS
approved