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A289034 Fixed point of the morphism 0->010, 1->10 starting with 1. 3
1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0 (list; graph; refs; listen; history; text; internal format)
OFFSET
1
COMMENTS
Old name was: 1-limiting word of reversed iterates of the mapping 0->01, 1->0, starting with 0.
The first seven iterates of the mapping 0->01, 1->0, starting with 0, are:
0
01
010
01001
01001010
0100101001001
010010100100101001010
with limit the infinite Fibonacci word A003849.
The corresponding reversed iterates are as follows:
0
10
010
10010
01010010
1001001010010
010100101001001010010
The 1-limiting word is the limit of the n-th iterates for n == 1 mod 2. (The 0-limiting word is A189661.)
There is a simple way to construct this. Let sigma be the time-reversed Fibonacci morphism, i.e., the morphism sigma: 0->10, 1->0. Then sigma^2 is given by 0->010, 1->10, and sigma^2 has two fixed points. The fixed point starting with 1 is the present sequence. - Michel Dekking, Oct 18 2018
LINKS
EXAMPLE
The first four n-th reversed iterates for n == 1 mod 2 are these:
10
10010
1001001010010
1001001010010010100101001001010010
MATHEMATICA
z = 13; (*number of iterates*)
s = {0}; w[0] = StringJoin[Map[ToString, s]];
w[n_] := StringReplace[w[n - 1], {"0" -> "01", "1" -> "0"}];
r[n_] := StringReverse[w[n]];
TableForm[Table[r[n], {n, 0, 8}]]
rw = ToCharacterCode[r[z]] - 48 (* A289034 *)
p0 = Flatten[Position[rw, 0]]; (* A099267 *)
p1 = Flatten[Position[rw, 1]]; (* A007066 *)
CROSSREFS
Cf. A003849, A189661, A099267, A007066, A287523 (binary complement), A188432.
Sequence in context: A068429 A285208 A260444 * A011747 A089013 A188374
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Jul 10 2017
EXTENSIONS
Name changed by Michel Dekking, Oct 20 2018
STATUS
approved

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Last modified April 23 10:29 EDT 2024. Contains 371905 sequences. (Running on oeis4.)