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Positions of 1 in A288936; complement of A288937.
3

%I #4 Jun 28 2017 22:25:38

%S 3,6,7,9,10,12,13,14,16,17,18,19,21,22,23,24,25,27,28,29,30,31,32,34,

%T 35,36,37,38,39,40,42,43,44,45,46,47,48,49,51,52,53,54,55,56,57,58,59,

%U 61,62,63,64,65,66,67,68,69,70,72,73,74,75,76,77,78,79,80

%N Positions of 1 in A288936; complement of A288937.

%C a(n)/n -> 1.

%H Clark Kimberling, <a href="/A288938/b288938.txt">Table of n, a(n) for n = 1..10000</a>

%t z = 11; (* number of iterates *)

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "0010", "01" -> "011", "10" -> "011"}]

%t TableForm[Table[w[n], {n, 0, 10}]]

%t st = ToCharacterCode[w[z]] - 48 (* A288936 *)

%t Flatten[Position[st, 0]] (* A288937 *)

%t Flatten[Position[st, 1]] (* A288938 *)

%Y Cf. A288936, A288937.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Jun 28 2017