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A288745
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Number of Dyck paths of semilength n such that the maximal number of peaks per level equals four.
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2
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1, 1, 11, 38, 163, 648, 2571, 10173, 40025, 156087, 605057, 2335566, 8980883, 34412583, 131431024, 500437733, 1900135511, 7196366668, 27191450135, 102522926104, 385785153584, 1448985664032, 5432879981201, 20337296148823, 76015000686028, 283720418696600
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OFFSET
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4,3
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LINKS
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MAPLE
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b:= proc(n, k, j) option remember; `if`(j=n, 1, add(
b(n-j, k, i)*add(binomial(i, m)*binomial(j-1, i-1-m),
m=max(0, i-j)..min(k, i-1)), i=1..min(j+k, n-j)))
end:
g:= proc(n, k) option remember; add(b(n, k, j), j=1..k) end:
a:= n-> g(n, 4)-g(n, 3):
seq(a(n), n=4..35);
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MATHEMATICA
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b[n_, k_, j_]:=b[n, k, j]=If[j==n, 1, Sum[b[n - j, k, i] Sum[Binomial[i, m] Binomial[j - 1, i - 1 - m], {m, Max[0, i - j], Min[k, i - 1]}], {i, Min[j + k, n - j]}]]; g[n_, k_]:=Sum[b[n, k, j], {j, k}]; Table[g[n, 4] - g[n, 3], {n, 4, 35}] (* Indranil Ghosh, Aug 08 2017 *)
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PROG
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(Python)
from sympy.core.cache import cacheit
from sympy import binomial
@cacheit
def b(n, k, j): return 1 if j==n else sum([b(n - j, k, i)*sum([binomial(i, m)*binomial(j - 1, i - 1 - m) for m in range(max(0, i - j), min(k, i - 1) + 1)]) for i in range(1, min(j + k, n - j) + 1)])
def g(n, k): return sum([b(n, k, j) for j in range(1, k + 1)])
def a(n): return g(n, 4) - g(n, 3)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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