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A288603
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a(n) = 2*a(n-1) - a(n-3) for n >= 3, where a(0) = 2, a(1) = 4, a(2) = 6, a(3) = 8.
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2
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2, 4, 6, 8, 12, 18, 28, 44, 70, 112, 180, 290, 468, 756, 1222, 1976, 3196, 5170, 8364, 13532, 21894, 35424, 57316, 92738, 150052, 242788, 392838, 635624, 1028460, 1664082, 2692540, 4356620, 7049158, 11405776, 18454932, 29860706, 48315636, 78176340, 126491974
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OFFSET
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0,1
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COMMENTS
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Conjecture: a(n) is the number of letters (0's and 1's) in the n-th iteration of the mapping 00->0101, 1->1001, starting with 00; see A288600.
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LINKS
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FORMULA
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a(n) = 2*a(n-1) - a(n-3) for n >= 3, where a(0) = 2, a(1) = 4, a(2) = 6, a(3) = 8.
G.f.: 2*(1 - x^2 - x^3)/(1 - 2*x + x^3).
a(n) = Fibonacci(n) + Lucas(n) + 2 for n >= 1. - Greg Dresden, Oct 10 2020
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MATHEMATICA
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Join[{2}, LinearRecurrence[{2, 0, -1}, {4, 6, 8}, 40]]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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