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Positions of 1 in A288381; complement of A288382.
3

%I #4 Jun 10 2017 22:30:59

%S 4,6,7,9,10,11,12,14,15,16,17,18,19,20,21,23,24,25,26,27,28,29,30,31,

%T 32,33,34,35,36,37,38,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,

%U 56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,73,74,75

%N Positions of 1 in A288381; complement of A288382.

%C a(n+1)/a(n)-> 1.

%H Clark Kimberling, <a href="/A288383/b288383.txt">Table of n, a(n) for n = 1..10000</a>

%F a(n) = -1 + A288133(n-1) for n >= 2.

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "0001", "1" -> "11"}]

%t Table[w[n], {n, 0, 8}]

%t st = ToCharacterCode[w[11]] - 48 (* A288381 *)

%t Flatten[Position[st, 0]] (* A288382 *)

%t Flatten[Position[st, 1]] (* A288383 *)

%Y Cf. A288381, A288382.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Jun 10 2017