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A287957 Table read by antidiagonals: T(n, k) = greatest common recursive divisor of n and k; n > 0 and k > 0. 3
1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 2, 3, 2, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 4, 1, 2, 1, 1, 1, 3, 1, 1, 3, 1, 1, 1, 2, 1, 2, 5, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 3, 2, 1, 6, 1, 2, 3, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 1, 2, 7, 2, 1 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
1,5
COMMENTS
We use the definition of recursive divisor given in A282446.
More informally, the prime tower factorization of T(n, k) is the intersection of the prime tower factorizations of n and k (the prime tower factorization of a number is defined in A182318).
This sequence has connections with the classical GCD (A003989).
For any i > 0, j > 0 and k > 0:
- T(i, j) = 1 iff gcd(i, j) = 1,
- A007947(T(i, j)) = A007947(gcd(i, j)),
- T(i, j) >= 1,
- T(i, j) <= min(i, j),
- T(i, j) <= gcd(i, j),
- T(i, 1) = 1,
- T(i, i) = i,
- T(i, j) = T(j, i) (the sequence is commutative),
- T(i, T(j, k)) = T(T(i, j), k) (the sequence is associative),
- T(i, i*j) <= i,
- if gcd(i, j) = 1 then T(i*j, k) = T(i, k) * T(j, k) (the sequence is multiplicative),
- T(i, 2*i) = A259445(i).
See also A287958 for the LCM equivalent.
LINKS
EXAMPLE
Table starts:
n\k| 1 2 3 4 5 6 7 8 9 10
---+-----------------------------------------------
1 | 1 1 1 1 1 1 1 1 1 1 ...
2 | 1 2 1 2 1 2 1 2 1 2 ...
3 | 1 1 3 1 1 3 1 1 3 1 ...
4 | 1 2 1 4 1 2 1 2 1 2 ...
5 | 1 1 1 1 5 1 1 1 1 5 ...
6 | 1 2 3 2 1 6 1 2 3 2 ...
7 | 1 1 1 1 1 1 7 1 1 1 ...
8 | 1 2 1 2 1 2 1 8 1 2 ...
9 | 1 1 3 1 1 3 1 1 9 1 ...
10 | 1 2 1 2 5 2 1 2 1 10 ...
...
T(4, 8) = T(2^2, 2^3) = 2.
PROG
(PARI) T(n, k) = my (g=factor(gcd(n, k))); return (prod(i=1, #g~, g[i, 1]^T(valuation(n, g[i, 1]), valuation(k, g[i, 1]))))
CROSSREFS
Sequence in context: A353282 A350714 A159923 * A003989 A091255 A332013
KEYWORD
nonn,tabl,mult
AUTHOR
Rémy Sigrist, Jun 03 2017
STATUS
approved

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Last modified April 25 07:07 EDT 2024. Contains 371964 sequences. (Running on oeis4.)